Problems
1. 4x +5=13
2. 3z -6= 27
2. 3z -6= 27
Explanation
-We must box the variable, circle the coefficient, and under line the constant.
-We will get rid of the 5 or -6 that is added(subtracted) by subtracting(adding) 5 or -6 from both sides.
-Soon we will have a one step equation.(4x=8 & 3z=21)
This still leaves a +4 or +3 in front of the variable so we will have to divide both sides by +4 +3.
-Soon we will get our solution. ( x=2 & x=7)
-If you are not satisfied about the answer you got, than you can check your answer.
-However, when you check your work, it is very different from solving the questions.
-Instead of using a variable you substitute x=2 . For example, 4 x 2 +5=13 & 3 x 7 +6=27
-You have to multiply first. ( 4 x 2=8 & 3 x 7=21)
-Then you add your answer with the positive number. ( 8 + 5= 13 & 21 + 6=27)
-If you DID get the correct answer, then you did the problem right.
-If you DIDN'T get the correct answer, you must go back and re-do the equation.
-We will get rid of the 5 or -6 that is added(subtracted) by subtracting(adding) 5 or -6 from both sides.
-Soon we will have a one step equation.(4x=8 & 3z=21)
This still leaves a +4 or +3 in front of the variable so we will have to divide both sides by +4 +3.
-Soon we will get our solution. ( x=2 & x=7)
-If you are not satisfied about the answer you got, than you can check your answer.
-However, when you check your work, it is very different from solving the questions.
-Instead of using a variable you substitute x=2 . For example, 4 x 2 +5=13 & 3 x 7 +6=27
-You have to multiply first. ( 4 x 2=8 & 3 x 7=21)
-Then you add your answer with the positive number. ( 8 + 5= 13 & 21 + 6=27)
-If you DID get the correct answer, then you did the problem right.
-If you DIDN'T get the correct answer, you must go back and re-do the equation.